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Proof step 4 from proof bits2int-sign (previous step)

⊦ bits2int(bits0 + boolvar ' + bits1) = bits2int(boolvar ' + bits1), (¬ boolvar) ∈ bits0

User applied rule cut formula

And obtained the following new goals

Proof step 5:
⊦ bits0 = [], bits2int(bits0 + boolvar ' + bits1) = bits2int(boolvar ' + bits1), (¬ boolvar) ∈ bits0

Rule argument

fma: bits0 = []

Additional information

Used simplifier rules: ⊦ [] + bits = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used formulas: bits0 = []