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Proof step 18 from proof bits2int-split-01 (previous step)

# bits0 ≠ 0 ⊦ bits2uint((false ' + bitsinvert(bits1))+1) * 2 ^ n→i(# bits0) + bits2uint(bits0) = (bits2uint(bitsinvert(bits1)) * 2 ^ n→i(# bits0) + bits2uint(bitsinvert(bits0))) + 1, bits0 = [], true ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
⊦ bits0 = [], bits2uint((false ' + bitsinvert(bits1))+1) * 2 ^ n→i(# bits0) = (bits2uint(bitsinvert(bits1)) * 2 ^ n→i(# bits0) + bits2uint(bitsinvert(bits0))) + 1, true ∈ bits0

Rule argument

Additional information

Used simplifier rules: bits2uint-zeros: ⊦ ¬ true ∈ bits → bits2uint(bits) = 0;% ⊦ # bits = 0 ↔ bits = [];% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + 0 = i;