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Proof step 22 from proof bits2int-split-01 (previous step)

⊦ bits0 = [], 2 ^ n→i(# bits0) = bits2uint(bitsinvert(bits0)) + 1, true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2uint(bits) = 2 ^ n→i(# bits) - 1

Rule argument

name: bits2uint-ones rotate: F subst: [bits] → [bitsinvert(bits0)]

Additional information

Used simplifier rules: ⊦ # bitsinvert(bits) = # bits;% ⊦ i + (j - i) = j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ false ∈ bitsinvert(bits) ↔ true ∈ bits;% ⊦ bitsinvert(bits) = [] ↔ bits = []; Used terms: bitsinvert(bits0)