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Proof step 6 from proof bits2int-split (previous step)

⊦ bits0 = [], bits2uint(bits1 + bits0) = bits2uint(bits0) + 2 ^ n→i(# bits0) * bits2uint(bits1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ # bits0 ≠ 0 → bits2uint(bits + bits0) = bits2uint(bits) * 2 ^ n→i(# bits0) + bits2uint(bits0)

Rule argument

name: bits2uint-split rotate: F subst: [bits0, bits] → [bits0, bits1]

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j = j + i;% ⊦ # bits = 0 ↔ bits = []; Used terms: bits0, bits1