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Proof step 14 from proof bits2int-zero-02 (previous step)

0 ≤ n→i(# bits0), bits2uint(bits0) + 2 ^ n→i(# bits0) = 2 ^ n→i(# bits0) * 2 ⊦ bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
2 ^ n→i(# bits0) = bits2uint(bits0) ⊦ bits0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ 0 ≤ n→i(n);% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 1 * i = i;% ⊦ (* i2) * i = i + j0 ↔ (i2 - 1) * i = j0;