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Proof step 3 from proof bits2int-zeros-01 (previous step)

⊦ bits = [], bits2int(bits + false ' + bits0) = bits2uint(bits0), true ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits.rest)
Proof step 5:
¬(¬ (bits + false ' + bits0).first ∧ bits + false ' + bits0 ≠ []) ⊦ bits = [], bits2int(bits + false ' + bits0) = bits2uint(bits0), true ∈ bits
Proof step 7:
¬ (bits + false ' + bits0).first ∧ bits + false ' + bits0 ≠ [] ⊦ bits = [], bits2uint((bits + false ' + bits0).rest) = bits2uint(bits0), true ∈ bits

Rule argument

name: bits2int-pos-01 rotate: F subst: [bits] → [bits + false ' + bits0]

Additional information

Used terms: bits + false ' + bits0