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Proof step 2 from proof bits2int-zeros (previous step)

⊦ n = 0, bits2int(mklist(false, n) + bits) = bits2uint(bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits.rest)
Proof step 4:
¬ (mklist(false, n) + bits).first ∧ mklist(false, n) + bits ≠ [] ⊦ n = 0, bits2uint((mklist(false, n) + bits).rest) = bits2uint(bits)

Rule argument

name: bits2int-pos-01 rotate: F subst: [bits] → [mklist(false, n) + bits]

Additional information

Used simplifier rules: ⊦ n ≠ 0 → ((mklist(boolvar, n) + bits).first ↔ boolvar);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ mklist(boolvar, m) = [] ↔ m = 0; Used terms: mklist(false, n) + bits