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Proof step 1 from proof bits2int16-02 (conclusion)

⊦ 16 < # bits → ¬ bits2int(lastn(16, bits)) < ~32768

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bits2int(lastn(16, bits)) < 0, 16 < # bits, bits2int(lastn(16, bits)) < ~32768 ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ m < n → n ≠ 0; (forward)