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Proof step 1 from proof bits2int8-01 (conclusion)

⊦ # bits = 8 → ¬ 127 < bits2int(bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits = 8, 127 < bits2int(bits), 0 < bits2int(bits), 0 ≤ bits2int(bits) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)