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Proof step 1 from proof bits2int8-03 (conclusion)

⊦ 8 < # bits → ¬ 127 < bits2int(lastn(8, bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ bits2int(lastn(8, bits)), 0 < bits2int(lastn(8, bits)), 8 < # bits, 127 < bits2int(lastn(8, bits)) ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)% ⊦ m < n → n ≠ 0; (forward)