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Proof step 1 from proof bits2int8 (conclusion)

⊦ # bits = 8 → ¬ bits2int(bits) < ~128

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits = 8, bits2int(bits) < ~128, bits2int(bits) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)