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Proof step 2 from proof bits2uint-2pot-01 (previous step)

⊦ bits2uint(false ' + true ' + bits) = 2 ^ n→i(# bits), true ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits2uint(false ' + bits) = bits2uint(bits)
Proof step 4:
⊦ bits2uint(true ' + bits) = 2 ^ n→i(# bits), true ∈ bits

Rule argument

name: bits2uint-zeros-03 rotate: F subst: [bits] → [true ' + bits]

Additional information

Used terms: true ' + bits