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Proof step 2 from proof bits2uint-2pot (previous step)

⊦ bits2uint(true ' + bits) = 2 ^ n→i(# bits), true ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bits0 ≠ 0 → bits2uint(bits + bits0) = bits2uint(bits) * 2 ^ n→i(# bits0) + bits2uint(bits0)
Proof step 4:
¬ # bits ≠ 0 ⊦ bits2uint(true ' + bits) = 2 ^ n→i(# bits), true ∈ bits
Proof step 5:
# bits ≠ 0 ⊦ bits2uint(true ') * 2 ^ n→i(# bits) + bits2uint(bits) = 2 ^ n→i(# bits), true ∈ bits

Rule argument

name: bits2uint-split rotate: F subst: [bits0, bits] → [bits, true ']

Additional information

Used terms: bits, true '