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Proof step 5 from proof bits2uint-inv-neg (previous step)

⊦ bits = [], 2 ^ n→i(# bits) = bits2uint(bitsinvert(bits)) + bits2uint(bits) + 1, bits.first

User applied rule induction

And obtained the following new goals

Proof step 6:
true, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ 2 ^ n→i(# bits0) = bits2uint(bitsinvert(bits0)) + bits2uint(bits0) + 1 ∨ bits0.first ⊦ bits = [] ∨ 2 ^ n→i(# bits) = bits2uint(bitsinvert(bits)) + bits2uint(bits) + 1 ∨ bits.first

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits