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Proof step 5 from proof bits2uint-nle (previous step)

2 ^ n→i(# bits) ≤ bits2uint(bits), 2 + # bits ≤ # uint2bits(bits2uint(bits)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ uint2bits(bits2uint(bits)) = sgn(false ' + bits)

Rule argument

name: ubits2ubits-def rotate: F subst: [bits] → [bits]

Additional information

Used simplifier rules: ⊦ ¬ 2 + # bits ≤ # sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: bits