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Proof step 1 from proof bits2uint-not-neg (conclusion)

⊦ bits2uint(bits) ≤ 0 ↔ bits2uint(bits) = 0

User applied rule induction

And obtained the following new goals

Proof step 2:
true, ∀ bits0. # bits0 < # bits → true → (bits2uint(bits0) ≤ 0 ↔ bits2uint(bits0) = 0) ⊦ bits2uint(bits) ≤ 0 ↔ bits2uint(bits) = 0

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits