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Proof step 3 from proof bits2uint-not-zero (previous step)

bits2uint(bits) = 0 ∧ true ∈ bits, ∀ bits0. # bits0 < # bits → bits2uint(bits0) = 0 ∧ true ∈ bits0 → false ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information