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Proof step 12 from proof bits2uint-split (previous step)

bits2uint(bits + bits1) = bits2uint(bits) * 2 ^ n→i(# bits1) + bits2uint(bits1), ∀ bits2, bits. # bits2 < #(bits1 + false ') → true → bits2uint(bits + bits2) = bits2uint(bits) * 2 ^ n→i(# bits2) + bits2uint(bits2) ∨ bits2 = [] ⊦ bits2uint(bits + bits1) * 2 = 2 ^ (n→i(# bits1) + 1) * bits2uint(bits) + bits2uint(bits1) * 2, bits1 = []

User applied rule insert equation

And obtained the following new goals

Proof step 13:
∀ bits2, bits. # bits2 < #(bits1 + false ') → true → bits2uint(bits + bits2) = bits2uint(bits) * 2 ^ n→i(# bits2) + bits2uint(bits2) ∨ bits2 = [] ⊦ (bits2uint(bits) * 2 ^ n→i(# bits1) + bits2uint(bits1)) * 2 = 2 ^ (n→i(# bits1) + 1) * bits2uint(bits) + bits2uint(bits1) * 2, bits1 = []

Rule argument

pos: left 1 flags: discard

Proof step 12 from proof bits2uint-split (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information