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Proof step 1 from proof bits2uint-zero-01 (conclusion)

⊦ bits2uint(fillsgn(n, int2bits(i))) = 0 ↔ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ 0 ≤ j → bits2uint(fillsgn(n, int2bits(j))) = j
Proof step 3:
¬ 0 ≤ i ⊦ bits2uint(fillsgn(n, int2bits(i))) = 0 ↔ i = 0

Rule argument

name: int2uint-fill rotate: F subst: [j, n] → [i, n]

Additional information

Used terms: i, n