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Proof step 4 from proof bits2uint-zero-01 (previous step)

bits2uint(fillsgn(n, int2bits(i))) = 0, i < 0 ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ true ∈ bits → bits2uint(bits) ≠ 0
Proof step 6:
¬ true ∈ fillsgn(n, int2bits(i)), bits2uint(fillsgn(n, int2bits(i))) = 0, i < 0 ⊦ i = 0

Rule argument

name: bits2uint-not-zero rotate: F subst: [bits] → [fillsgn(n, int2bits(i))]

Additional information

Used terms: fillsgn(n, int2bits(i))