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Proof step 2 from proof bits2uint-zeros-01 (previous step)

⊦ bits2uint(bitsinvert(bits)) = 0, false ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ true ∈ bits → bits2uint(bits) = 0

Rule argument

name: bits2uint-zeros rotate: F subst: [bits] → [bitsinvert(bits)]

Additional information

Used simplifier rules: ⊦ true ∈ bitsinvert(bits) ↔ false ∈ bits; Used terms: bitsinvert(bits)