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Proof step 5 from proof bits2uint-zeros-02 (
previous step
)
⊦ bits2uint(bits) = 0, true ∈ bits
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 6
:
⊦ ¬ true ∈ bits → bits2uint(bits) = 0
Rule argument
name: bits2uint-zeros rotate: F subst: [bits] → [bits]
Additional information
Used terms: bits