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Proof step 9 from proof int2bits-2pot-03 (previous step)

¬(¬ false ∈ bits ∧ 0 ≤ j), uint2bits(j) = false ' + true ' + bits, 0 ≤ j ⊦ 2 ^ n→i(# uint2bits(j).rest) = j + 1, false ∈ uint2bits(j).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
uint2bits(j) = false ' + true ' + bits, 0 ≤ j, false ∈ bits ⊦ 2 ^ n→i(# uint2bits(j).rest) = j + 1, false ∈ uint2bits(j).rest

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;