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Proof step 1 from proof int2bits-2pot-04 (conclusion)

0 ≤ i, j ≠ 0 ⊦ int2bits(j * 2 ^ i) = int2bits(j) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i ⊦ j = 0, int2bits(j * 2 ^ i) = int2bits(j) + mklist(false, i→n(i))

Rule argument

Additional information