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Proof step 15 from proof int2bits-2pot-04 (previous step)

¬ false ∈ mklist(true, i→n(i)), j < 2 ^ i, 0 < 2 ^ i, 0 ≤ i, j * 2 ^ i < i, j < i, j + 1 < 2 ^ i, j < 0 ⊦ j = 0, sgn(bitsinvert(uint2bits(~ j)) +1 + bitsinvert(mklist(true, i→n(i)))) = int2bits(j) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
j < 2 ^ i, 0 < 2 ^ i, 0 ≤ i, j * 2 ^ i < i, j < i, j + 1 < 2 ^ i, j < 0 ⊦ j = 0, sgn(bitsinvert(uint2bits(~ j)) +1 + mklist(false, i→n(i))) = int2bits(j) + mklist(false, i→n(i))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ false ∈ mklist(true, n);% ⊦ bitsinvert(mklist(boolvar, n)) = mklist(¬ boolvar, n);