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Proof step 17 from proof int2bits-2pot-04 (previous step)

i = 0, j < 2 ^ i, 0 < 2 ^ i, 0 ≤ i, j * 2 ^ i < i, j < i, j + 1 < 2 ^ i, j < 0 ⊦ j = 0, sgn(bitsinvert(uint2bits(~ j)) +1 + mklist(false, i→n(i))) = int2bits(j) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
j < 0 ⊦ j = 0, sgn(bitsinvert(uint2bits(~ j)) +1) = int2bits(j)

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 1 * i = i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i < 1 ↔ i ≤ 0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];