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Proof step 20 from proof int2bits-2pot-04 (previous step)

j < 2 ^ i, 0 < 2 ^ i, 0 ≤ i, j * 2 ^ i < i, j < i, j + 1 < 2 ^ i, j < 0 ⊦ i = 0, j = 0, sgn(bitsinvert(uint2bits(~ j)) +1 + mklist(false, i→n(i))) = int2bits(j) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
0 < i, 0 < 2 ^ i, j < 2 ^ i, j < 0, j + 1 < 2 ^ i, j < i, j * 2 ^ i < i, j + 1 < i ⊦ sgn(bitsinvert(uint2bits(~ j)) +1 + mklist(false, i→n(i))) = int2bits(j) + mklist(false, i→n(i)), j = 0, i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i +1 = i + 1;% ⊦ i < j ∧ j < i0 → i +1 < i0; (forward)% ⊦ i ≠ j → (i ≤ j ↔ i < j);