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Proof step 4 from proof int2bits-2pot-04 (previous step)

¬ 0 ≤ j * 2 ^ i, 0 ≤ i ⊦ j = 0, int2bits(j * 2 ^ i) = int2bits(j) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ i, j * 2 ^ i < 0, j * 2 ^ i < i ⊦ j = 0, int2bits(j * 2 ^ i) = int2bits(j) + mklist(false, i→n(i))

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;