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Proof step 3 from proof int2bits-2pot-05 (previous step)

~(j * 2 ^ i) = ~ j * 2 ^ i, 0 ≤ i ⊦ int2bits(~(j * 2 ^ i)) = int2bits(~ j) + mklist(false, i→n(i)), 0 = j

User applied rule insert equation

And obtained the following new goals

Proof step 4:
0 ≤ i ⊦ int2bits(~ j * 2 ^ i) = int2bits(~ j) + mklist(false, i→n(i)), 0 = j

Rule argument

pos: left 1 flags: discard

Additional information