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Proof step 4 from proof int2bits-2pot-neg-mone (previous step)

0 ≤ j * 2 ^ i - 1, 0 < j, 0 < i ⊦ uint2bits(j * 2 ^ i - 1) = int2bits(j - 1) + mklist(true, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j, 0 < i, 0 ≤ i ⊦ uint2bits(j * 2 ^ i - 1) = int2bits(j - 1) + mklist(true, i→n(i))

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < 2 ^ i ↔ 0 ≤ i;% ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;