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Proof step 8 from proof int2bits-add-high (
previous step
)
⊦ j < 0 ∧ j0 < 0 ∧ abs(j0) < 2 ^ i ∧ 0 ≤ i → # int2bits(~(j * 2 ^ i + j0)) = # int2bits(~ j) + i→n(i)
Lemma
int2bits-len-add