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Proof step 8 from proof int2bits-eq (previous step)

sgn(bitsinvert(uint2bits(~ j)) +1) = false ', j < 0 ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ bits ≠ [] → (sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits)

Rule argument

seq: ⊦ bits ≠ [] → (sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits) subst: [boolvar, bits] → [false, bitsinvert(uint2bits(~ j)) +1] rotate: F spec: bitopsaux inst: name: sgn-one-01

Additional information

Used simplifier rules: ⊦ ¬ bits +1 ≠ [] ↔ false;% ⊦ ¬ true ∈ bits +1 ↔ false; Used terms: false, bitsinvert(uint2bits(~ j)) +1