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Proof step 4 from proof int2bits-exneg (previous step)

i < 0, i < ~1, i < 0 ⊦ ∃ bits. sgn(bitsinvert(uint2bits(abs(i))) +1) = true ' + false ' + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < ~1, i < 0 ⊦ ∃ bits. sgn(bitsinvert(uint2bits(~ i)) +1) = true ' + false ' + bits

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;