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Proof step 12 from proof int2bits-falsein-01 (previous step)

bits = boolvar + bits1, uint2bits(~ i) = bits + true ' + bits0, bitsinvert(uint2bits(~ i)) +1 = bitsinvert(bits) + true ' + bits0, i < 0, i < ~1 ⊦ boolvar, bits = [], true ∈ bits0, false ∈ sgn(bitsinvert(bits) + true ' + bits0).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
uint2bits(~ i) = (false ' + bits1) + true ' + bits0, bitsinvert(uint2bits(~ i)) +1 = (true ' + bitsinvert(bits1)) + true ' + bits0, i < 0, i < ~1, false ∈ uint2bits(~ i) ⊦ true ∈ bits0, false ∈ sgn((true ' + bitsinvert(bits1)) + true ' + bits0).rest

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ boolvar ' + bits ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bitsinvert(false ' + bits) = true + bitsinvert(bits);% ⊦ boolvar + bits = boolvar ' + bits;