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Proof step 24 from proof int2bits-falsein-01 (previous step)

bitsinvert(bits1) ≠ [], uint2bits(~ i) = (false ' + bits1) + true ' + bits0, bitsinvert(uint2bits(~ i)) +1 = (true ' + bitsinvert(bits1)) + true ' + bits0, i < 0, i < ~1, false ∈ uint2bits(~ i) ⊦ bits1 = [], true ∈ bits0, false ∈ sgn((true ' + bitsinvert(bits1)) + true ' + bits0).rest, bitsinvert(bits1).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
uint2bits(~ i) = (false ' + bits1) + true ' + bits0, bitsinvert(uint2bits(~ i)) +1 = (true ' + bitsinvert(bits1)) + true ' + bits0, i < 0, i < ~1, false ∈ uint2bits(~ i) ⊦ bits1 = [], true ∈ bits0, false ∈ sgn((true ' + bitsinvert(bits1)) + true ' + bits0).rest, bitsinvert(bits1).first

Rule argument

Additional information

Used simplifier rules: ⊦ bitsinvert(bits) = [] ↔ bits = [];