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Proof step 32 from proof int2bits-falsein-01 (previous step)

bits0 = [], uint2bits(~ i) = (false ' + bits1) + true ' + bits0, bitsinvert(uint2bits(~ i)) +1 = (true ' + bitsinvert(bits1)) + true ' + bits0, i < 0, i < ~1, false ∈ uint2bits(~ i) ⊦ bits1 = [], bitsinvert(bits1).first, (bitsinvert(bits1) + true ').first, true ∈ bits0, false ∈ bits0, true ∈ bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
uint2bits(~ i) = false ' + bits1 + true ', bitsinvert(uint2bits(~ i)) +1 = true ' + bitsinvert(bits1) + true ', i < 0, i < ~1, false ∈ uint2bits(~ i) ⊦ bits1 = [], bitsinvert(bits1).first, (bitsinvert(bits1) + true ').first, true ∈ bits1

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ boolvar ∈ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;