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Proof step 61 from proof int2bits-falsein-01 (previous step)

bitsinvert(bits1) ≠ [], uint2bits(~ i) = false ' + bits1 + true ', bitsinvert(uint2bits(~ i)) +1 = true ' + bitsinvert(bits1) + true ', i < 0, i < ~1, false ∈ uint2bits(~ i), bitsinvert(bits1).first, true ∈ bits1 ⊦ bits1 = [], false ∈ sgn(bitsinvert(bits1)).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 62:
uint2bits(~ i) = false ' + bits1 + true ', bitsinvert(uint2bits(~ i)) +1 = true ' + bitsinvert(bits1) + true ', i < 0, i < ~1, false ∈ uint2bits(~ i), bitsinvert(bits1).first, true ∈ bits1 ⊦ bits1 = [], false ∈ sgn(bitsinvert(bits1)).rest

Rule argument

Additional information

Used simplifier rules: ⊦ bitsinvert(bits) = [] ↔ bits = [];