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Proof step 63 from proof int2bits-falsein-01 (previous step)

bitsinvert(bits1) = boolvar + bits ∧ bitsinvert(bits1) ≠ [], uint2bits(~ i) = false ' + bits1 + true ', bitsinvert(uint2bits(~ i)) +1 = true ' + bitsinvert(bits1) + true ', i < 0, i < ~1, false ∈ uint2bits(~ i), boolvar, true ∈ bits1 ⊦ bits1 = [], false ∈ sgn(bitsinvert(bits1)).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 64:
uint2bits(~ i) = false ' + (false ' + bitsinvert(bits)) + true ', bitsinvert(uint2bits(~ i)) +1 = true ' + (true ' + bits) + true ', false ∈ uint2bits(~ i), i < ~1, i < 0, false ∈ bits ⊦ false ∈ sgn(true ' + bits).rest

Rule argument

Additional information

Used simplifier rules: ⊦ true ∈ bitsinvert(bits) ↔ false ∈ bits;% ⊦ false ∈ bitsinvert(bits) ↔ true ∈ bits;% ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);% ⊦ boolvar ' + bits ≠ [];% ⊦ bitsinvert(bitsinvert(bits)) = bits;% ⊦ bitsinvert(false ' + bits) = true + bitsinvert(bits);% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ bitsinvert(bits) = [] ↔ bits = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;%⊦ bitsinvert(bits) = true ' + bits0 ↔ bits = false ' + bitsinvert(bits0);% ⊦ boolvar + bits = boolvar ' + bits;