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Proof step 10 from proof int2bits-falsein-02 (previous step)

2 ^ i = j + 1, j < ~1, j < 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ j = i0 + j0 ↔ j - j0 = i0

Rule argument

seq: ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0 subst: [j0, i0, j] → [1, j, 2 ^ i] rotate: F spec: int-abs inst: name: numadd-01

Additional information

Used simplifier rules: ⊦ i - j < i0 ↔ i < j + i0;% ⊦ ¬ 2 ^ i < 0; Used terms: 1, j, 2 ^ i