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Proof step 2 from proof int2bits-first-03 (previous step)

int2bits(j) = true ' + bits, 0 < j ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ j → int2bits(j) ≠ true ' + bits

Rule argument

name: int2bits-first-04 rotate: F subst: [bits, j] → [bits, j]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: bits, j