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Proof step 2 from proof int2bits-first-04 (previous step)

int2bits(j) = true ' + bits, 0 < j ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used simplifier rules: uint2bits-first-01: ⊦ 0 ≤ i → uint2bits(i) ≠ true ' + bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: j