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Proof step 1 from proof int2bits-first (conclusion)

⊦ j < 0 → int2bits(j) ≠ false ' + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
int2bits(j) = false ' + bits, j < 0, false ∈ int2bits(j) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)