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Proof step 4 from proof int2bits-first (previous step)

j < 0, sgn(bitsinvert(uint2bits(abs(j))) +1) = false ' + bits, j < 0, false ∈ sgn(bitsinvert(uint2bits(abs(j))) +1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
sgn(bitsinvert(uint2bits(~ j)) +1) = false ' + bits, j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ i < 0 → abs(i) = ~ i;