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Proof step 1 from proof int2bits-lelen-02 (conclusion)

⊦ i < ~1 ∧ 0 ≤ j → (2 ^ j + i < 0 ↔ ¬ # int2bits(i) ≤ i→n(j) + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 0, 0 ≤ j, i < ~1, i < j ⊦ 2 ^ j + i < 0 ↔ ¬ # int2bits(i) ≤ i→n(j) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)