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Proof step 2 from proof int2bits-lelen-05 (previous step)

i < ~1, i < 0 ⊦ m ≤ # int2bits(i) ↔ ¬ 0 ≤ i + 2 ^ (n→i(m) - 2)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < ~1 ∧ 0 ≤ j → (0 ≤ 2 ^ j + i ↔ # int2bits(i) ≤ i→n(j) + 1)
Proof step 4:
¬(i < ~1 ∧ 0 ≤ n→i(m) - 2), i < ~1, i < 0 ⊦ m ≤ # int2bits(i) ↔ ¬ 0 ≤ i + 2 ^ (n→i(m) - 2)
Proof step 7:
i < ~1 ∧ 0 ≤ n→i(m) - 2, i < ~1, i < 0 ⊦ m ≤ # int2bits(i) ↔ ¬ # int2bits(i) ≤ i→n(n→i(m) - 2) + 1

Rule argument

spec: int2bits inst: name: int2bits-lslen-02 seq: ⊦ i < ~1 ∧ 0 ≤ j → (0 ≤ 2 ^ j + i ↔ # int2bits(i) ≤ i→n(j) + 1) subst: [i, j] → [i, n→i(m) - 2] flags: rewrite, current

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: i, n→i(m) - 2