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Proof step 15 from proof int2bits-lelen-07 (previous step)

j < 0, 1 + # int2bits(~ j) < # int2bits(j) ⊦ j + 2 ^ n→i(# int2bits(~ j)) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ ¬(∃ i. j = ~(2 ^ i)) ∧ j < 0 → # int2bits(j) = # int2bits(~ j)
Proof step 17:
¬(¬(∃ i. j = ~(2 ^ i)) ∧ j < 0), j < 0, 1 + # int2bits(~ j) < # int2bits(j) ⊦ j + 2 ^ n→i(# int2bits(~ j)) = 0

Rule argument

name: int2bits-len-neg-02 rotate: F subst: [j] → [j]

Additional information

Used simplifier rules: ⊦ ¬ m + n < m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: j