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Proof step 6 from proof int2bits-lelen-07 (previous step)

j < 0, 2 ^ n→i(# int2bits(~ j)) + j ≤ 0 ⊦ ¬ 0 ≤ j ∧ j + 2 ^ n→i(# int2bits(~ j)) ≠ 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: int2bits-len-eq-01: ⊦ 2 ^ n→i(# int2bits(~ j)) + j ≠ 0;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);