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Proof step 1 from proof int2bits-len-abs (conclusion)

⊦ ¬ # int2bits(j) + 1 < # int2bits(~ j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# int2bits(j) + 1 < # int2bits(~ j) ⊦

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)