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Proof step 4 from proof int2bits-len-abs (previous step)

¬(¬(∃ i. j = ~(2 ^ i)) ∧ j < 0), # int2bits(j) + 1 < # int2bits(~ j) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# int2bits(j) + 1 < # int2bits(~ j) ⊦ 2 ^ i + j ≠ 0 ∧ ¬ 0 ≤ j

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ~ i = j ↔ i + j = 0;