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Proof step 5 from proof int2bits-len-eq (previous step)

j = 2 ^ n→i(# int2bits(j)), ¬ j ≤ 0 → 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1) ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 6:
j < 0, j = 2 ^ n→i(# int2bits(j)), ¬ j ≤ 0 → 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1) ⊦
Proof step 12:
j = 2 ^ n→i(# int2bits(j)), ¬ j ≤ 0 → 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1) ⊦ j < 0

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0